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🟢 — masalani tezlashtiradi · 🟡 — ilg'or daraja · 🔵 — chuqur o'rganish (olimpiada darajasi)

🟢 Kub formulalari

(a+b)3=a3+3a2b+3ab2+b3(a−b)3=a3−3a2b+3ab2−b3(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3 \qquad (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3

a3+b3=(a+b)(a2−ab+b2)a3−b3=(a−b)(a2+ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2) \qquad a^3 - b^3 = (a - b)(a^2 + ab + b^2)

🟢 Kvadratlar bilan ayniyatlar

a2+b2=(a+b)2−2ab(a+b)2−(a−b)2=4ab(a+b)2+(a−b)2=2(a2+b2)a^2 + b^2 = (a + b)^2 - 2ab \qquad (a + b)^2 - (a - b)^2 = 4ab \qquad (a + b)^2 + (a - b)^2 = 2(a^2 + b^2)

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

🔵 Uch o'zgaruvchili ayniyatlar

a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)

Natija: a+b+c=0a + b + c = 0 bo'lsa, a3+b3+c3=3abca^3 + b^3 + c^3 = 3abc.

a2+b2+c2−ab−bc−ca=12[(a−b)2+(b−c)2+(c−a)2]≥0a^2 + b^2 + c^2 - ab - bc - ca = \tfrac{1}{2}\left[(a - b)^2 + (b - c)^2 + (c - a)^2\right] \ge 0

🔵 Umumiy darajalar ayirmasi

xn−an=(x−a)(xn−1+axn−2+a2xn−3+⋯+an−1)x^n - a^n = (x - a)\left(x^{n-1} + a x^{n-2} + a^2 x^{n-3} + \dots + a^{n-1}\right)

a4+a2b2+b4=(a2+ab+b2)(a2−ab+b2)a^4 + a^2b^2 + b^4 = (a^2 + ab + b^2)(a^2 - ab + b^2)

Mashq qiling

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