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🟢 — masalani tezlashtiradi · 🟡 — ilg'or daraja · 🔵 — chuqur o'rganish (olimpiada darajasi)

🟢 Ko'rsatkichli tenglamalar (bir xil asosga keltirish)

a>0a > 0, a≠1a \ne 1 bo'lsa:   ax=ay  ⇒  x=y\;a^x = a^y \;\Rightarrow\; x = y

Misol: 4x−3⋅2x+2=04^x - 3 \cdot 2^x + 2 = 0. u=2xu = 2^x desak, u2−3u+2=0u^2 - 3u + 2 = 0, u=1u = 1 yoki u=2u = 2, ya'ni x=0x = 0 yoki x=1x = 1.

🟡 Logarifm qoidalari

log⁡a(xy)=log⁡ax+log⁡aylog⁡axy=log⁡ax−log⁡aylog⁡axn=nlog⁡ax\log_a(xy) = \log_a x + \log_a y \qquad \log_a\frac{x}{y} = \log_a x - \log_a y \qquad \log_a x^n = n\log_a x

log⁡aa=1log⁡a1=0alog⁡ax=xlog⁡ab=ln⁡bln⁡a\log_a a = 1 \qquad \log_a 1 = 0 \qquad a^{\log_a x} = x \qquad \log_a b = \frac{\ln b}{\ln a}

  • ax=b  ⇒  x=ln⁡bln⁡aa^x = b \;\Rightarrow\; x = \dfrac{\ln b}{\ln a}

🟡 Ko'rsatkichli va logarifmik juftlik

y=ex  ↔  y=ln⁡xeln⁡x=x  (x>0)ln⁡ex=xy = e^x \;\leftrightarrow\; y = \ln x \qquad e^{\ln x} = x \;(x > 0) \qquad \ln e^x = x

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