Mavzular

⭐ — imtihonda eng ko'p ishlatiladigan formulalar. · 🟢 — masalani tezlashtiradi · 🟡 — ilg'or daraja · 🔵 — chuqur o'rganish (olimpiada darajasi)

Radian o'lchov

  • 1 radian — yoy uzunligi radiusga teng bo'lgan markaziy burchak (≈57.3°\approx 57.3°).
  • ⭐ π radian=180°\pi \text{ radian} = 180°. Gradusdan radianga: ×π180\times\dfrac{\pi}{180}; radiandan gradusga: ×180π\times\dfrac{180}{\pi}.
Gradus30°30°45°45°60°60°90°90°180°180°360°360°
Radianπ6\frac{\pi}{6}π4\frac{\pi}{4}π3\frac{\pi}{3}π2\frac{\pi}{2}π\pi2π2\pi
  • ⭐ Yoy uzunligi: s=rθs = r\theta (θ\theta radianda)
  • ⭐ Sektor yuzi: A=12r2θA = \frac{1}{2}r^2\theta (θ\theta radianda)

Sektor bilan bog'liq formulalar

  • Sektor perimetri: P=2r+rθP = 2r + r\theta
  • Vatar uzunligi: AB=2rsin⁡θ2AB = 2r\sin\dfrac{\theta}{2}
  • ⭐ Segment yuzi: A=12r2(θ−sin⁡θ)A = \frac{1}{2}r^2(\theta - \sin\theta)

🟢 Graduslarda sektor

yoy=θ360°⋅2πrsektor=θ360°⋅πr2\text{yoy} = \frac{\theta}{360°} \cdot 2\pi r \qquad \text{sektor} = \frac{\theta}{360°} \cdot \pi r^2

🟢 Sektor va segment

  • Sektor perimetri: P=2r+rθP = 2r + r\theta
  • Vatar: AB=2rsin⁡θ2AB = 2r\sin\dfrac{\theta}{2}
  • Segment yuzi: 12r2(θ−sin⁡θ)\frac{1}{2}r^2(\theta - \sin\theta)
  • Segment perimetri: rθ+2rsin⁡θ2r\theta + 2r\sin\dfrac{\theta}{2}

🔵 Burchak tezlik

v=rω(ω — rad/s)v = r\omega \qquad (\omega \text{ — rad/s})