Mavzular

Mavzular / Ketma-ketliklar va binom

Binom yoyilmasi

Test: 10 ta savol, vaqt bilan

4 ta oson, 4 ta oʻrta, 2 ta qiyin. Tez va toʻgʻri javob — koʻproq ball.

Testni boshlash

Yoki quyida mashq qiling: variantni tanlang — javob va izoh chiqadi. Ball berilmaydi.

Oson · 5 ta

1.

(2x−1)3(2x - 1)^3 yoyilmasida barcha koeffitsientlar yigʻindisini toping.

2.

(1+x)9(1 + x)^9 yoyilmasida x5x^5 oldidagi koeffitsientni toping.

3.

(1x+3)6(1x + 3)^6 yoyilmasida barcha koeffitsientlar yigʻindisini toping.

4.

(1+x)5(1 + x)^5 yoyilmasida x2x^2 oldidagi koeffitsientni toping.

5.

(1x+2)3(1x + 2)^3 binom yoyilmasida nechta had bor?

Oʻrta · 5 ta

1.

(2x−3)6(2x - 3)^6 yoyilmasida x4x^4 oldidagi koeffitsientni toping.

2.

(x−3)4(x - 3)^4 yoyilmasida x1x^1 oldidagi koeffitsientni toping.

3.

(2x+2)4(2x + 2)^4 yoyilmasida x3x^3 oldidagi koeffitsientni toping.

4.

(x−2)7(x - 2)^7 yoyilmasida x4x^4 oldidagi koeffitsientni toping.

5.

(2x−3)6(2x - 3)^6 yoyilmasida x2x^2 oldidagi koeffitsientni toping.

Qiyin · 5 ta

1.

(x+3x2)6\left(x + \frac{3}{x^2}\right)^{6} yoyilmasida xx qatnashmagan hadni toping.

2.

(2x+2)4(2x + 2)^4 yoyilmasining oʻrtadagi hadi x2x^2 oldidagi koeffitsientni toping.

3.

(x+4x2)6\left(x + \frac{4}{x^2}\right)^{6} yoyilmasida xx qatnashmagan hadni toping.

4.

(2x+2)6(2x + 2)^6 yoyilmasining oʻrtadagi hadi x3x^3 oldidagi koeffitsientni toping.

5.

(x+3x2)3\left(x + \frac{3}{x^2}\right)^{3} yoyilmasida xx qatnashmagan hadni toping.

Yordam